(3b-5)^2+9b=(4+b)(4-b)

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Solution for (3b-5)^2+9b=(4+b)(4-b) equation: 



(3b-5)^2+9b=(4+b)(4-b)

We move all terms to the left:

(3b-5)^2+9b-((4+b)(4-b))=0

We add all the numbers together, and all the variables

(3b-5)^2+9b-((b+4)(-1b+4))=0

We add all the numbers together, and all the variables

9b+(3b-5)^2-((b+4)(-1b+4))=0

We multiply parentheses ..

-((-1b^2+4b-4b+16))+9b+(3b-5)^2=0



We calculate terms in parentheses: -((-1b^2+4b-4b+16)), so:

(-1b^2+4b-4b+16)

We get rid of parentheses

-1b^2+4b-4b+16

We add all the numbers together, and all the variables

-1b^2+16

Back to the equation:

-(-1b^2+16)



We get rid of parentheses

1b^2+9b+(3b-5)^2-16=0

We add all the numbers together, and all the variables

b^2+9b+(3b-5)^2-16=0

We move all terms containing b to the left, all other terms to the right

b^2+9b+(3b-5)^2=16

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